Quantitative Aptitude: Quadratic Equations Set 23

Directions: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

I. 7x² – 9x + 2 = 0
II. y² – 4y + 3 = 0
A) If x > y
B) If x < y
C) If x ≥ y
D) If x ≤ y
E) If x = y or relation cannot be established

View Answer
Option D
Solution:
I. 7x²– 7x – 2x + 2 = 0
or, 7x(x – 1) – 2(x – 1) = 0
(7x – 2) (x – 1) = 0
or, x =2/7 , 1
II. y²– y – 3y + 3 = 0
or, y(y – 1) – 3(y – 1) = 0
or, (y – 3) (y – 1) = 0
y = 1, 3
x <= y
I. x²+ x – 20 = 0
II. 2y² – 19y + 45 = 0
A) If x > y
B) If x < y
C) If x ≥ y
D)If x ≤ y
E) If x = y or relation cannot be established

View Answer
Option B
Solution:
I. x²+ x – 20 = 0
or, x²+ 5x – 4x – 20 = 0
or, x(x + 5) – 4(x + 5) = 0
or, (x – 4) (x + 5) = 0
x = 4, – 5
II. 2y²– 10y – 9y + 45 = 0
or, 2y(y – 5) – 9(y – 5) = 0
or, (y – 5) (2y – 9) = 0
y = 5 , 9/2
I. 7x + 3y = 26
II. 2x + 17y = -41
A) If x > y
B) If x < y
C) If x ≥ y
D) If x ≤ y
E) If x = y or relation cannot be established

View Answer
Option A
Solution:
Eqn (I) × 2
Eqn (II) × 7
14x + 6y = 52
14x + 119y = – 287
– 113y = 339
y = – 3 and x = 5, ie x > y
I. 3x² – 20x + 33 = 0
II. 2y² – 11y + 15 = 0
A) If x > y
B) If x < y
C) If x ≥ y
D) If x ≤ y
E) If x = y or relation cannot be established

View Answer
Option C
Solution:
I. 3x²– 9x – 11x + 33 = 0
or, 3x(x – 3) – 11(x – 3) = 0
or, (3x – 11) (x – 3) = 0
x = 3, 11/3
II. 2y²– 6y – 5y + 15 = 0
or, 2y(y – 3) – 5(y – 3) = 0
or, (y – 3) (2y – 5) = 0
y = 3 , 5/2
I. 5x² + 2x – 3 = 0
II. 2y²+ 7y + 6 = 0
A) If x > y
B) If x < y
C) If x ≥ y
D) If x ≤ y
E) If x = y or relation cannot be established

View Answer
Option A
Solution:
5x²+ 5x – 3x – 3 = 0
or 5x (x + 1) – 3(x + 1) = 0
or (5x – 3) (x + 1) = 0
x= 3/5, -1
II. 2y²+ 4x + 3y + 6 = 0
or 2y(y + 2) + 3(y + 2) =0
or (2y + 3) (y + 2) = 0
y = -3/2 , -2
I. 35x² – 53x + 20 = 0
II. 56y² -97y + 42 = 0
A) If x > y
B) If x < y
C) If x ≥ y
D) If x ≤ y
E)If x = y or relation cannot be established

View Answer
Option B
Solution:
I. 35x² – 28x – 25x + 20 = 0
or 7x(5x – 4) – 5(5x – 4) = 0
or (7x – 5) (5x – 4) = 0
x 5/7 , 4/5
II. 56y² – 48y – 49y + 42 = 0
or 8y(7y – 6) – 7(7y – 6) = 0
or (8y – 7) (7y – 6) = 0
y = 7/8 , 6/7
I. x = 3√4913
II. 13y + 3x = 246
A) If x > y
B) If x < y
C) If x ≥ y
D) If x ≤ y
E) If x = y or relation cannot be established

View Answer
Option A
Solution:
I. x = 3√4913
x = 17

II. 13y = 246 – 3x
or 13y = 246 – 51 = 195
y = 15
x > y
I. x² – 5x – 14 = 0
II. y²+ 7y + 10 = 0
A) If x > y
B) If x < y
C) If x ≥ y
D)If x ≤ y
E) If x = y or relation cannot be established

View Answer
Option C
Solution:
I. x²– 7x + 2x – 14 = 0
or x(x – 7) + 2(x – 7) = 0
(x + 2) (x – 7) = 0
x = -2, 7
II. y²+ 5y + 2y + 10 = 0
or y(y + 5) + 2(y + 5) = 0
or (y + 2) (y + 5) = 0
y = -2, -5
x ≥ y
I. x²= 64
II. 2y² + 25y + 72 = 0
A) If x > y
B) If x < y
C) If x ≥ y
D) If x ≤ y
E)If x = y or relation cannot be established

View Answer
Option E
Solution:
I. x²= 64
x = ±8
II. 2y²+ 9y + 16y + 72 = 0
or, y(2y + 9) + 8(2y + 9) = 0
or, (y + 8) (2y + 9) = 0
y = -8 , -9/2
no relation between x and y.
I. x² – 3481 = 0
II. 3y² = 3√216000
A) If x > y
B) If x < y
C) If x ≥ y
D) If x ≤ y
E)If x = y or relation cannot be established

View Answer
Option E
Solution:
I. x²= 3481
x = ± 59
II. 3y²= 3√216000
3y2= 60
y = ± √20
No relation

$~$PrAdeEP$K$~$~$

July 10, 2017 at 4:49 pm

go to di section of this page if u havnt visited previously …:))
1. $~$PrAdeEP$K$~$~$
  
  July 10, 2017 at 4:59 pm
  
  okkkk..don’t vorry….i will convey ur request to our respectful mods….:))
2. Ambika
  
  July 10, 2017 at 5:01 pm
  
  Yes we ll post soon 🙂
  1. karthik
    
    July 10, 2017 at 5:31 pm
    
    again equations are very easy.. oops.
  2. Ambika
    
    July 10, 2017 at 5:54 pm
    
    yes sure …we ll post soon
  3. EKTA
    
    July 11, 2017 at 12:06 pm
    
    mam plsss maths and reasonong ke jada se jada quiz post kijiye,,,time is very less , we need to improve a lot
    1. Ambika
      
      July 11, 2017 at 2:37 pm
      
      yes we ll post 🙂
      keep practising old sets bhi dobara kar liya kro 1-2 times usse tumhare concept or achhe se clear ho jayenge
      1. EKTA
        
        July 11, 2017 at 5:24 pm
        
        yess mam i am doing old one also….thank u mam…..
karthik

July 10, 2017 at 5:33 pm

second one answer wrong.
1. Ambika
  
  July 10, 2017 at 5:57 pm
  
  yess corrected
KaRi$hMa

July 10, 2017 at 5:48 pm

2nd nd 4th ques. answer wrong..please rectify it..ty..:):)
1. Ambika
  
  July 10, 2017 at 5:56 pm
  
  yess i ll edit 🙂
  1. KaRi$hMa
    
    July 10, 2017 at 6:42 pm
    
    okk….:):) puzzles m bht tym lg rha h jo aj wali thi na unme….bht din bad ki h isliye….ap btao aj wali puzzle kitne min. m bnni chahiye…sahi speed??
Sourav Kumar

July 10, 2017 at 5:49 pm

Yes second1 is wrng
DR. Jhatka

July 10, 2017 at 7:27 pm

thanku ambika mam 🙂
Jellyfish

July 10, 2017 at 7:35 pm

2)B
4)c
Pls edit it
1. yuvi
  
  July 10, 2017 at 7:43 pm
  
  bro 4th should be C..
yuvi

July 10, 2017 at 7:44 pm

mam..2-b
4-c
plzz correct it..
1. Jellyfish
  
  July 10, 2017 at 7:46 pm
  
  Yes sorry 4)c
AVI™ (Sinchen loveR)

July 11, 2017 at 4:29 pm

thnxxx :))
Ayushi

July 31, 2017 at 12:19 am

thanku..mam que 10 m 2nd eqn 60/3 =20 than 20 ka square root nhi nikalana kya i mean y =+20/-20 or root 20
1. Shubhra
  
  July 31, 2017 at 12:14 pm
  
  yes
  root to be taken.
?Jab Harry Met Sejal(4-Aug)?

July 31, 2017 at 12:09 pm

plz check 10th Ques
2nd Equation solution
1. Shubhra
  
  July 31, 2017 at 12:14 pm
  
  yes
  root to be taken
Chotu D(mind) !! {NONSENSE}

September 2, 2017 at 12:43 am

done